7.25x^2-15x+1=0

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Solution for 7.25x^2-15x+1=0 equation:



7.25x^2-15x+1=0
a = 7.25; b = -15; c = +1;
Δ = b2-4ac
Δ = -152-4·7.25·1
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-14}{2*7.25}=\frac{1}{14.5} =1/14.5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+14}{2*7.25}=\frac{29}{14.5} =2 $

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